## Leetcode : Number of digit one

Problem Statement Solution: The brute force approach would be iterate through all numbers from 0 to N and then for each number count the number of 1's and add them up. For a number N, the number of digits it contains is O(log10N). Thus the brute force approach has a time complexity of O(N*log10N). Can we do better than this ? The proposed solution achieves a O(log10N) run-time complexity. The […]